Question

A 20 ft ladder leans against a wall. The bottom of the ladder is 3 ft from the wall at time t=0 and slides away from the wall at a rate of 2ft/sec. Find the velocity of the top of the ladder at time t=1.

Answer 1

Answer: 0.516 ft/s

Step-by-step explanation:

Given

Length of ladder L=20 ft

The speed at which the ladder moving away is v=2 ft/s

after 1 sec, the ladder is 5 ft away from the wall

So, the other end of the ladder is at

`\Rightarrow y=√(20^2-5^2)=19.36\ ft`

Also, at any instant t

`\Rightarrow l^2=x^2+y^2`

differentiate w.r.t.

`\Rightarrow 0=2xv+2yv_y\\\\\Rightarrow v_y=-(x)/(y)* v\\\\\Rightarrow v_y=-(5)/(19.36)* 2=0.516\ ft/s`