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A fixed 14.1-cm-diameter wire coil is perpendicular to a magnetic field 0.52 T pointing up. In 0.28 s , the field is changed to 0.23 T pointing down. Part A What is the average induced emf in the coil

User Tal Cohen
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1 Answer

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12 votes

Answer:

the average induced emf in the coil is 0.016 V.

Step-by-step explanation:

Given;

diameter of the wire, d = 14.1 cm = 0.141 m

change in magnetic filed strength, dB = 0.52 T - 0.23 T = 0.29 T

change in time, dt = 0.28 s

The area of the wire is calculated as follows;


A = (\pi d^2)/(4) \\\\A = (\pi * (0.141)^2)/(4) \\\\A = 0.0156 \ m ^2

The induced emf is calculated as follows;


emf = (dBA)/(dt) \\\\emf = (0.29 * 0.0156)/(0.28) \\\\emf = 0.016 \ V

Therefore, the average induced emf in the coil is 0.016 V.

User Eligos
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