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Lead has a density of 11.4 g/cm
How many grams would 80 mm³ of lead weigh?

User Kevin Boyd
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5.2k points

2 Answers

5 votes

Final Answer:

80 mm³ of lead would weigh 0.912 grams.

Step-by-step explanation:

Given that the density of lead is 11.4 g/cm³, to find the weight of 80 mm³ of lead, the density formula (Density = Mass / Volume) can be rearranged to find the mass (Mass = Density × Volume).

First, convert 80 mm³ to cm³. Since 1 cm³ = 1 mL, the conversion is straightforward: 80 mm³ is equivalent to 0.08 cm³ (80 mm³ ÷ 1000 = 0.08 cm³).

Now, use the formula Mass = Density × Volume. Multiply the density of lead (11.4 g/cm³) by the volume in cm³ (0.08 cm³) to find the mass. Mass = 11.4 g/cm³ × 0.08 cm³ = 0.912 grams.

Understanding density as a measure of mass per unit volume helps in calculating the mass or weight of a substance given its volume and density. Converting units appropriately, such as from mm³ to cm³, ensures consistency in calculations involving volume.

Knowing the relationship between density, mass, and volume enables precise measurements and calculations in various scientific fields, including chemistry, physics, and material sciences.

User Trogper
by
4.8k points
2 votes

Answer:

0.912 grams

Step-by-step explanation:

from Density =Mass/volume

mass= Density × volume

  1. hence mass= ( 11.4 × 10^⁶g/m³) × (80×10^-⁹m³)
  2. mass=0.912g
User Delcon
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5.0k points