Question

A ball strikes the pavement with a force of 5.0 N. If the pressure exerted on the

pavement is 9.6 x 103 Pa, what is the area of contact between the ball and the
pavement?

Answer 1

≈ 5.21 N

Step-by-step explanation:

The formula for pressure is
`P=(F)/(A\\)`, with P being the pressure, F the force, and A the area of contact.

Since we are given that the force is
`5.0` N and the pressure is
`9.6*10x^(3)`, we can figure out the area of contact by rearranging the formula a bit.

1) You multiply A on both sides to get F alone:

`P*A=(F)/(A) *A`

2) Then you divide P on both sides to get A alone:

`(P*A)/(P) =(F)/(P)`

3) Then you plug in the numbers given:

`A=(5.0)/(9.6 * 10^(3) )`

4) And finally you just solve:

`(5.0)/(9.6 * 10^(3) )` ≈
`5.208` or
`5.21`

Answer 2

Step-by-step explanation:

Given:

F = 5.0 N

p = 9.6·10³ Pa

____________

S - ?

S = F / p = 5.0 / 9.6·10³ ≈ 0,52·10⁻³ м² = 5.2 cm²