Question

Please help me to find answer as soon as possible.......​

Answer 1

APOS is isosceles as
• PO = OS, because diagonals of rectangle bisect each-other
Hence OPS and _OSP of APOS
are equal
• (180° -124°)/2 = 56°/2 = 28°
_PQO is complementary with ¿PSO
• mzPQ0 = 90° - 28º = 62°
¿OQR is same as PSO as APOS = AROQ
• m¿OQR = 28°

Answer 2

ΔPOS is isosceles as

• PO = OS, because diagonals of rectangle bisect each-other

Hence ∠OPS and ∠OSP of ΔPOS are equal

• (180° - 124°)/2 = 56°/2 = 28°

∠PQO is complementary with ∠PSO

• m∠PQO = 90° - 28° = 62°

∠OQR is same as ∠PSO as ΔPOS ≅ ΔROQ

• m∠OQR = 28°