Answer:
No solutions
Explanation:

Add 8 on both sides to make it into the form ax^2 + bx + c = 0
x^2 - 3x + 8 = -8 + 8
x^2 - 3x + 8 = 0
Now it is in the correct form, we can plug our numbers in.
a: 1
b: -3
c: 8


Because the discriminant, or b^2 - 4ac is negative, there are no solutions.