Question

HELP WITH THESE TWO PROBS PLEASE

Answer 1

1. She is moving at a speed of
`147.18 ms^(-1)`.

2. The speed of the golf ball is
`78.1 m/s`.

Step-by-step explanation:

1. We can say , at any moment the skydiver is having a kinetic energy of
`1/2 mv^2`

(where,
`m` is her mass and
`v` is the velocity at that point)

Given,
`1/2mv^2 =704000`

and,
`m = 65KG`

So, putting the values we get,

`v=147.18 ms^(-1)`

2.
`KE=(1)/(2) mv^2`

`143.3J =(1)/(2) (.047)v^2`

`v^2=6097.9 m^2/s^2`

`v=78.1 m/s`