Question

when the 171st even positive integer is subtracted from the 219th odd positive integer, the result is z. Find z.

Answer 1

To find z, we calculate the 171st even positive integer (342) and subtract it from the 219th odd positive integer (437), resulting in z = 95.

Step-by-step explanation:

The student is asking about the difference between two specific integers: the 171st even positive integer and the 219th odd positive integer. To find the 171st even positive integer, you would use the formula 2n, where n is the integer's position in the sequence. So for n = 171, the 171st even positive integer is 2(171) = 342. To find the 219th odd positive integer, you use the formula 2n - 1, since the first odd positive integer is 1, the second is 3, and so on. For n = 219, the 219th odd positive integer is 2(219) - 1 = 437. The difference z is then 437 - 342 = 95.

Answer 2

Even number =2n
Odd number =2m+1
171st even = 2(171)
219th odd = 2(219)+1
2(171)-(2(219)+1)=-97
z=-97