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Write a recursive method called sumTo that accepts an integer parameter n and returns a real number representing the sum of the first n reciprocals. In other words, sumTo(n) returns (1 1/2 1/3 1/4 ... 1/n). For example, sumTo(2) should return 1.5. The method should return 0.0 if it is passed the value 0 and throw an IllegalArgumentException if it is passed a value less than 0.

User Thomiel
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1 Answer

7 votes
7 votes

Answer:

Sorry mate I tried it was wrong

Step-by-step explanation:

Sorry again

User WaterNotWords
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