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Given that 10-√32 / √2 =a+b√2 where a and b are integers. Find the values of a and b. ​

Given that 10-√32 / √2 =a+b√2 where a and b are integers. Find the values of a and b. ​
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Given that 10-√32 / √2 =a+b√2 where a and b are integers. Find the values of a and b. ​

User Saeed Foroughi
by
8.2k points

1 Answer

6 votes

Answer:


a=-5, b=5

Explanation:


(10-√(32))/(√(2)) \\ \\ =(10-5√(2))/(√(2)) \\ \\ =(10)/(√(2))-5 \\ \\ =5√(2)-5 \\ \\ \therefore a=-5, b=5

User Nche
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