Question

Use point-slope form to write the equation of a line that passes through the point

(-13,-19) with slope 7/6.

Answer 1

`(\stackrel{x_1}{-13}~,~\stackrel{y_1}{-19})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{7}{6} \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-19)}=\stackrel{m}{ \cfrac{7}{6}}(x-\stackrel{x_1}{(-13)}) \implies y +19= \cfrac{7}{6} (x +13)`