Question

2. When doing a chin-up, a physics student lifts her 42. 0-kg body a distance of

0. 25 meters in 2 seconds. What is the power delivered by the student's

biceps?

Answer 1

Answer: 51.45 W

Step-by-step explanation:

Work = W = Force x Displacement = Fd

W = (mg)(d) = (42 kg)(9.8 m/s2)(0.25 m) = 102.9 J

Force applied is equal to the weight of the student

Power = P = W/t = 102.9J / 2 s = 51.45 Watts