Question

how many liters of a 3.45 m m k2so4k2so4 solution are needed to provide 63.5 g g of k2so4k2so4 (molar mass 174.01 g/molg/mol )? recall that mm is equivalent to mol/lmol/l .

Answer 1

0.00011L of K2SO4 solution are needed to provide 63.5 g of K2SO4 with Molar mass of 174.01 g/mole .

Molarity of the solution is the number of moles per solute per liter of a solution .

Molarity =moles of solute / volume of the solution

moles of the solute is equals to the mass of the solute divided by the molar mass of the solution.

here given 3.45m K2SO4 solution are needed to provide 63.5 g of K2SO4.and the molar mass is 174.01g/mole . we have to find the molar quantity of the K2SO4.so we have to divide the given volume by molar mass. so, it becomes,

63.5g/ 174.01 g/mole = 0.364 mole

Volume = moles of solute /molarity

= 0.364 mole / 3.45M

= 0.00011 L

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