Question

what is the molarity of an aqueous solution that is 5.88% nacl by mass? (assume a density of 1.02 g/ml for the solution.) (hint: 5.88% nacl by mass means 5.88 g nacl/100.0 g solution.)

Answer 1

The molarity of the aqueous solution containing 5.88% NaCl by mass is 0.102 M.

Step-by-step explanation:

The molarity of an aqueous solution can be calculated using the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, we need to find the moles of NaCl in the solution. The mass percent of NaCl is given as 5.88%, which means there are 5.88 grams of NaCl per 100 grams of solution. Therefore, there are 5.88/58.44 = 0.1 moles of NaCl in 1000 grams of solution.

Now, we need to find the volume of the solution in liters. The density of the solution is given as 1.02 g/mL, which means 1000 grams of solution occupy a volume of 1000/1.02 = 980.39 mL or 0.98039 liters.

Finally, we can plug in the values into the formula:

Molarity = 0.1 moles / 0.98039 liters = 0.102 M