Question

What is the equation of the line that passes through the points (-2,5) and (0,-1)

Answer 1

y = 3x + 11

Explanation:

Slope (m)

m =
`(y_2-y_1)/(x_2-x_1)` =
`(-1-5)/(0 - (-2))` =
`(-6)/(2)` = -3

y = mx + b

y = 3x + b

(-2,5)

y = 3x + b

5 = 3(-2) + b

5 = -6 + b

+ 6 + 6

11 = b

y = 3x + 11

Check:

(-2,5)

y = 3x + 11

5 = 3(-2) + 11

5 = -6 + 11

5 = 5

Hope this helps!