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A fair six-sided die is rolled twice. What is the theoretical probability that the first number that comes up is greater than or equal to the second number?

OA. 1
6
OB. 1
2
O c. 7
12
O
D. 5

User Vadishev
by
7.6k points

1 Answer

0 votes

Answer:

c. 7/12

Explanation:

There are 36 possible outcomes when you roll a die twice.

11, 12, 13, 14, 15, 16

21, 22, 23, 24, 25, 26

31, 32, 33, 34, 35, 36

41, 42, 43, 44, 45, 46

51, 52, 53, 54, 55, 56

61, 62, 63, 64, 65, 66

The desired outcomes are the ones whose first number is greater than or equal to the second number. They are shown in bold and underline above.

There are 21 desired outcomes.

p(first number ≥ second number) = 21/36 = 7/12

Answer: c. 7/12

User Shenique
by
7.3k points