Question

HELP!

The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0

Answer 1

If y=width and (y+5)=length then A:
y(y+5)=750
If y=length and (y-5)=width Then B:
y(y-5)=750
and 3rd set everything = to
C: 750-y(y-5)=0

Answer 2

Answer:y(y +5)=750 y(y-5)=750 & 750-y(y-5)=0

Explanation:

If y=width and (y+5)=length then A: y( y+5)=750

If y=length and (y-5)=width Then B: y(y-5)=750

and 3rd set everything = to

C: 750-y(y-5)=0