Question

The reaction between nitric oxide (NO) and oxygen to form nitrogen dioxide (NO₂) is a key step in photochemical smog formation.

2 NO(g) + O₂(g) → 2 NO₂(g)
(a) How many moles of NO₂ are formed by the complete reaction of 0.234 mole of O₂?
moles
(b) How many grams of NO₂ are formed by the complete reaction of 3.04 g of NO?
grams

Answer 1

The complete reaction of 0.234 mole of O₂ will form 0.468 mole of NO₂. The complete reaction of 3.04 g of NO will form 4.652 g of NO₂.

Step-by-step explanation:

(a) To determine how many moles of NO₂ are formed by the complete reaction of 0.234 mole of O₂, we can use the balanced equation:

2 NO(g) + O₂(g) → 2 NO₂(g)

From the equation, we can see that for every 1 mole of O₂, 2 moles of NO₂ are formed. Therefore, with 0.234 mole of O₂, we can use the ratio:

0.234 mole O₂ × (2 mole NO₂/1 mole O₂) = 0.468 mole NO₂

Therefore, 0.234 mole of O₂ will form 0.468 mole of NO₂.

(b) To determine how many grams of NO₂ are formed by the complete reaction of 3.04 g of NO, we can use the molar mass of NO (30.01 g/mol) and the balanced equation:

2 NO(g) + O₂(g) → 2 NO₂(g)

First, we need to convert 3.04 g of NO to moles:

3.04 g NO × (1 mol NO/30.01 g NO) = 0.101 mol NO

From the equation, we can see that for every 2 moles of NO, 2 moles of NO₂ are formed. Therefore, with 0.101 mole of NO, we can use the ratio:

0.101 mole NO × (2 mole NO₂/2 mole NO) = 0.101 mole NO₂

Finally, we can convert the moles of NO₂ to grams using the molar mass of NO₂ (46.01 g/mol):

0.101 mol NO₂ × (46.01 g NO₂/1 mol NO₂) = 4.652 g NO₂

Therefore, 3.04 g of NO will form 4.652 g of NO₂.

Answer 2

a. 0.468 mole NO2

b. 4.66 g NO2

Step-by-step explanation:

a) Reaction: 2NO + O2 ----> 2NO2

Here 1 mole O2 produces 2 moles NO2

∴ 0.234 mole of O2 produces (2×0.234) mole of NO2

= 0.468 mole NO2

b) molecular mass of NO = 14 + 16 = 30 g

molecular mass of NO2 = 14 + (2×16) = 46 g

From the reaction we see

(2×30) g NO produces (2×46) g NO2

∴ 1 g NO produces (2×46)/(2×30) g NO2

∴ 3.04 g NO produces (2×46×3.04)/(2×30) g NO2

= 4.66 g NO2