Question

How fast would the moon need to travel in order to escape the gravitational pull of Earth, if Earth has a mass of 5.98 x 10^24 kg and the distance from Earth to the moon is 3.84 x 10^8 m?

Answer 1

Answer: 14.41*10^2 m/s

Step-by-step explanation:

let, V be the escape velocity of the moon.

M be the mass of the earth.

r be the distance between the moon and the earth.

G be the universal gravitational constant.

And G = 6.67428*10^-11 m^3kg^-1 s^-2

here, given in the question that

The earth has a mass of 5.98*10^24 kg.

so, M = 5.98*10^24 kg.

And the distance from the earth to the moon is 3.84*10^8 m.

so, r = 3.84*10^8 m.

now, we know,

V = √2GM/r

V = √(2 * 6.67428*10^-11* 5.98 * 10^24 )/ 3.84*10^8

V = √79.82*10^13/3.84*10^8

V = √20.78*10^5

V = 14.41*10^2 m/s