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What is the solution to -4(8-3x) ≥ 6x - 8?

O
4
x²--1/32
O x≤
xs--1/72
Ox≥4
Ox≤4

User GWu
by
3.6k points

1 Answer

4 votes

Answer:

x ≥ 4

Explanation:

-4 ( 8 - 3x ) ≥ 6x - 8

First, solve the brackets.

- 32 + 12x ≥ 6x - 8

Subtract 6x from both sides.

- 32 + 12x - 6x ≥ - 8

- 32 + 6x ≥ - 8

Add 32 to both sides.

6x ≥ - 8 + 32

6x ≥ 24

Divide 6 by both sides.

x ≥ 4

User Paul Rougieux
by
3.4k points