Question

HELP!

Find three consecutive odd integers such that twice the sum of the second and the third is 43 more than three times the first

Answer 1

Answer: 31, 33, and 35

Explanation:

Let’s set up a model for an odd integer: 2x+1. This number has to be odd because it’s an even number plus 1. 3 consecutive days numbers would be 2x+1, 2x+3, and 2-+5. Now we can set up the equations.
2(2x+3+2x+5)=43+3(2x+1)

Simplify:

4x+6+4x+10=43+6x+3

8x+16=6x+46

2x=30

x=15

Now put that back into our original number expressions:

2(15)+1, 2(15)+3, 2(15)+5

31, 33, and 35