Question

one container has a mass of 50kg, accurate to two significant figures. Another container has 62kg, also accurate to two significant figures. Find the interval, in the form of a ≤ x < b, of their possible total mass

Answer 1

m

i

​

=2.300kg ( 2 significant digits)

m

1

​

=20.15g=0.02015kg ( 4 significant digits)

m

2

​

=20.175g=0.02017kg ( 4 significant digits)

(a)

Adding

M=Σm=2.3+0.02015+0.02017kg=2.34032kg

But since the initial mass has least 2 signifincant digits, the final mass should not have more than 2 significant digits

Hence,

M=2.3Kg

(b)

Subtracting

m

2

​

−m

1

​

=0.02g

Since the initial mass has 4 significant digits, the result can have 4 or less significant digits

Hence here the no. of significant digit =2

Step-by-step step

you all welcome;)