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The area of a rectangular trampoline is 135 ft2. The length of the trampoline is 6 ft greater than the width of the trampoline. This situation can be represented by the equation w2+6w−135=0.

What is the width of the trampoline, in feet?

Question 7 options:

15 feet


5 feet


6 feet


9 feet

User Christosc
by
2.5k points

2 Answers

14 votes
14 votes

Answer :

  • 9 feet.

Explanation :

Given :

  • The area of a rectangular trampoline is 135 ft².
  • The length of the trampoline is 6 ft greater than the width of the trampoline.

To find :

  • The width of the trampoline.

Solution :

Let us assume the width of the rectangle as w and therefore the length becomes (w + 6) .

We know that,


{ \qquad \dashrightarrow \bf{Length * Width =Area _((rectangle)) }}

Substituting the values in the formula :


{\qquad \sf \dashrightarrow (w + 6)w = 135}


{\qquad \sf \dashrightarrow {w}^(2) + 6w = 135}


{\qquad \sf \dashrightarrow {w}^(2) + 6w - 135 = 0}


{\qquad \sf \dashrightarrow {w}^(2) + 15w - 9w - 135 = 0}


{\qquad \sf \dashrightarrow {w}(w + 15) - 9(w + 15) = 0}


{\qquad \sf \dashrightarrow (w + 15) (w - 9) = 0}


{\qquad \sf \dashrightarrow (w + 15) = 0}


{\qquad \sf \dashrightarrow w = - 15}


{\qquad \sf \dashrightarrow (w - 9) = 0}


{\qquad \sf \dashrightarrow w = 9}

  • Whether, w = (– 15) or 9 .

The width of the rectangle cannot be negative therefore the width of the rectangle must be 9 feet .

User Warpedspeed
by
2.4k points
21 votes
21 votes


\bold{\huge{\blue{\underline{ Solution }}}}

Given :-

  • The area of rectangular trampoline is 135ft².
  • The length of the trampoline is 6ft greater than the width of the trampoline .

To Find :-

  • We have to find the width of the trampoline

Let's Begin :-

We have,

  • Area of rectangular trampoline = 135ft²

Let the width of the rectangular trampoline be w

According to the question,

  • Length is 6ft greater than width

Therefore,

The length of the rectangular trampoline will be


\sf{ = (W + 6 )ft }

Now,

We know that,


\bold{\blue{ Area\: of\: rectangle = Length × Breath }}

Subsitute the required values,


\sf{ 135 = w(w + 6 ) }


\sf{ 135 = w² + 6w}


\sf{ = w² + 6w - 135 }

By factorization method,


\sf{ = w² - 9w + 15w - 135 }


\sf{ = w( w - 9) + 15( w - 9)}


\sf{ = ( w + 15) ( w - 9)}

Therefore,

Width of the rectangular trampoline


\sf{ w = - 15 \: or\: w = 9 }

[ Width of the rectangle can never be negative ]

Thus , The width of the rectangular trampoline is 9 feet


\bold{\pink{ Hence\:, Option \:D\: is\: correct }}

User Ryan Knight
by
2.4k points
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