Question

Find the equation of the line that contains the point (-1,-7) and is parallel to the line 6x + 5y = 11. Write the equation in slope-intercept form, if possible.

Answer 1

`y=-(6)/(5)x-(41)/(5)`

Explanation:

Parallel lines have the same slope.

`6x+5y=11 \\ \\ 5y=-6x+11 \\ \\ y=-(6)/(5)x+(11)/(5)`

So, the slope of the line we need to find is -6/5.

`y+7=-(6)/(5)(x+1) \\ \\ y+7=-(6)/(5)x-(6)/(5) \\ \\ y=-(6)/(5)x-(41)/(5)`