Question

On analysis of 3.4 mg of an organic compound, 8.03 g of CO2 and 3.34 g of H2O were obtained. The percentage composition of carbon and hydrogen in the compound are.......................... respectively​

Answer 1

Answer: The percentage composition of carbon and hydrogen in the compound are 64.4 % and 10.9 % respectively​

Step-by-step explanation:

Mass of
`CO_2` = 8.03 g

Mass of
`H_2O`= 3.34 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 8.03 g of carbon dioxide, =
`(12)/(44)* 8.03=2.19g` of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 3.34 g of water, =
`(2)/(18)* 3.34=0.371g` of hydrogen will be contained.

Mass of oxygen in the compound = (3.4) - (2.19+0.371) = 0.839 g

percent composition of C =
`\frac{\text{mass of C}}{\text{ Total mass}}* 100= (2.19)/(3.4)* 1000=64.4\%`

percent composition of H =
`\frac{\text{mass of H}}{\text{ Total mass}}* 100= (0.371)/(3.4)* 1000=10.9\%`

Thus the percentage composition of carbon and hydrogen in the compound are 64.4 % and 10.9 % respectively​