Answer:
Explanation:
You want the values of 'a' and 'k' so that the points (1, 20) and (2, 5) are on the graph of y = a(x +1)² +k.
Setup
The given (x, y) values can be used in the equation to give two equations in 'a' and 'k'.
(x, y) = (1, 20) ⇒ 20 = a(1+1)² +k = 4a +k
(x, y) = (2, 5) ⇒ 5 = a(2+1)² +k = 9a +k
Solution
Subtracting the first equation from the second gives ...
(5) -(20) = (9a +k) -(4a +k)
-15 = 5a . . . . . . simplify
-3 = a . . . . . . divide by 5
Using the first equation, we can find k:
20 = 4(-3) +k
32 = k . . . . . . . add 12
The values of 'a' and 'k' are ...