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31 votes
31 votes
A certain brand of flood lamps has a lifetime that is normally distributed with a mean

of 3,750 hours and a standard deviation of 300 hours.

(a) What proportion of these lamps will last for at least 4,000 hours?

(b) What proportion of these lamps will last between 3,600 and 4,000 hours?

(c) What proportion of these lamps will last less than 3,800?

User DerMike
by
2.6k points

2 Answers

23 votes
23 votes

Final answer:

The question involves calculating the proportion of flood lamps that will last for certain durations using the normal distribution characteristics of the product, with a mean of 3,750 hours and a standard deviation of 300 hours. Z-scores are computed to determine the percentages.

Step-by-step explanation:

The question relates to the normal distribution of a brand of flood lamps that has a mean lifetime of 3,750 hours and a standard deviation of 300 hours. To answer the various parts regarding the proportion of lamps that will last for different durations, the standard normal distribution (Z-score) will be used. The Z-score is calculated using the formula Z = (X - μ) / σ, where X is the value of interest, μ is the mean, and σ is the standard deviation.

  • (a) For lamps lasting at least 4,000 hours, the Z-score would be (4,000 - 3,750) / 300 = 0.83. We can then look up this Z-score in a standard normal table or use a calculator to find the corresponding percentage.
  • (b) To find the proportion between 3,600 and 4,000 hours, calculate the Z-scores for both 3,600 ((3,600 - 3,750) / 300 = -0.50) and 4,000, and find the area under the normal curve between these two Z-scores.
  • (c) For lamps lasting less than 3,800 hours, calculate the Z-score (-0.50) and lookup or calculate the cumulative probability.

The calculated proportions will provide the required probabilities for the respective timeframes.

User Buddah
by
2.5k points
18 votes
18 votes

Answer:

0.83

Step-by-step explanation:

(a) z = (x - mean) / sd = (4000 - 3750) / 300 = 0.83

This corresponds to 0.7967 from the z-table, which represents how many last less than 4000 hours, so the answer is 1 - 0.7967 = 0.2033

(b) It will be P(x<4000) - P(x>3600) = 0.7967 - whatever the corresponding value is.

(c) same procedure as (b).

(d) 2% above corresponds to 0.02 which is a z-score of -2.05

-2.05 = (x - 3750) / 300

x = 3135

User Jorge Rocha
by
2.8k points