Question

71. Distribution of Coins Emma paid the $10.36 bill for her lunch

with 232 coins consisting of pennies, nickels, and dimes. If the
number of nickels plus the number of dimes was equal to the num-
ber of pennies, then how many coins of each type did she use?

Answer 1

Answer: p = 116

n + d = 116n = 116 - d

6n + 11d = 1036

Explanation:

p + n + d = 232

n + d = p

p + 5n + 10d = 1036

p + 5n + 10d = 1036

n + d + 5n + 10d = 1036

6n + 11d = 1036

p + n + d = 232

n + d + n + d = 232

2n + 2d = 232

n + d = 116

n + d = p