Question

What would be the volume in liters of an 2.45 liter sample of gas at 594 °C

and 156 kPa if conditions were changed to STP?
1 atm = 101.3 kPa = 760 mmHg

Answer 1

`V_2= 1.19L`

Step-by-step explanation:

Hello there!

In this case, since the STP conditions are defined by 1 atm (101.3 kPa) and 273 K, it is possible for us to use the combined gas law for this problem as we are given variable pressure, temperature and volume:

`(P_1V_1)/(T_1) =(P_2V_2)/(T_2)`

In such a way, solving for V2 as the final volume, we obtain:

`V_2=(P_1V_1T_2)/(P_2T_1) =(156kPa*2.45L*273.15K)/(101.3kPa*(594+273)K)\\\\V_2= 1.19L`

Regards!