Question

Two positive charge spheres, the spheres are separated by 0.40 m. The charge on the first sphere is 100 microcoulombs and the

charge on the second sphere has 30 microcoulombs. Calculate the Electric Force on the charges?

Answer 1

Answer: 168.75 N

Step-by-step explanation:

first, let's convert microcoulombs to coulombs

q1 = 1e-4 C

q2 = 3e-5 C

r = 0.4 m

then use the equation Fe =
`(kq_(1) q_(2))/(r^(2) )`

plug in values --> F = (9e9*1e-4*3e-5)/(0.4)^2

F = 168.75 N