Question

Evaluate the intensity of solar radiation for 6 September 2021 , given solar constant ( Isc ) = 1800 W / m2

Answer 1

The answer is "
`1802.1978 \ (w)/(m^2)`"

Step-by-step explanation:

The Solar radiation reaches the earth surfaces is given by

`I=Isc(1+0.033 \cos (360.(n))/(365.25))`

where n is number of days in years

n for 6 September 2021:

`\to n= 31+28+31+30+31+30+31+31+6\\\\\to n= 249`

`\to I=Isc(1+0.033 \cos (360 \alpha 249)/(365.25))\\\\\to I=1800(1+0.033(+0.037))\\\\\to I =1800(1.001221)\\\\\to I=1802.1978 \ (w)/(m^2)`