Register
An object attached to a spring is pulled across a horizontal frictionless surface. If the force constant (spring constant) of the spring is 45 N/m and the spring is stretched by 0.88 m when the object
432,604 views
36 votes
36 votes
An object attached to a spring is pulled across a horizontal frictionless surface. If the force constant (spring constant) of the spring is 45 N/m and the spring is stretched by 0.88 m when the object is accelerating at 1.4 m/s2. What is the mass of the object?

User Atanamir
by
2.8k points

1 Answer

6 votes
6 votes

Answer:

28.3kg

Step-by-step explanation:

45=0.88*ml1.4

36.6=0.88m

divide through by 0.88

is said that

m=36.6/0.88

m=28.2857kg

User JamesWang
by
2.7k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers

Other Questions

After a light turns green , Lesly accelerates to 120 km/hr over 100 meters . What is her acceleration in m/s^2
If a constant fotce of 490 newtons is applied to an object and it proceeds to accelerate in the opposjte direction at 9.8 meters per second, every second, what is its mass?
How can I solve the following? In (Figure 1), let V = 15.0 V and C1=C2=C3= 24.2 μF. Part A: How much energy is stored in the capacitor network as shown in (Figure 1)? Part B: How much energy would be stored
1. if i start with 48 ml of water in a graduated cylinder, after submerging an object the water level rises to 63 ml, what is the volume of the object. 2. if i start with 36 ml of water in a graduated
Why is the system of si unit developed
Link Copied!