If $g(x)=\frac{1}{16}(3)^x,$ then $g\left(-2\right)=$ ?

asked Sep 12, 2023 135k views

4 votes

If $g(x)=\frac{1}{16}(3)^x,$
then $g\left(-2\right)=$ ?

$If $g(x)=\frac{1}{16}(3)^x,$ then $g\left(-2\right)=$ ?-example-1$

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2 votes

Answer:

g(- 2) =
(1)/(144)

Explanation:

substitute x = - 2 into g(x) , that is

g(- 2) =
(1)/(16) ×
3^(-2) =
×
(1)/(3^2) =
×
(1)/(9) =
(1)/(144)

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