If $g(x)=\frac{1}{16}(3)^x,$ then $g\left(-2\right)=$ ?

asked Sep 12, 2023 135k views

4 votes

If $g(x)=\frac{1}{16}(3)^x,$
then $g\left(-2\right)=$ ?

$If $g(x)=\frac{1}{16}(3)^x,$ then $g\left(-2\right)=$ ?-example-1$

8.5k points

Please log in or register to add a comment.

2 votes

Answer:

g(- 2) =
(1)/(144)

Explanation:

substitute x = - 2 into g(x) , that is

g(- 2) =
(1)/(16) ×
3^(-2) =
×
(1)/(3^2) =
×
(1)/(9) =
(1)/(144)

8.6k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers