Question

A letter is chosen at random from the word COMPUTER what is the probability that it is neither in the world MET nor in the world UP​

Answer 1

3/8

Explanation:

three of the 8 letters are not in the two given words

so p = 3/8

Answer 2

`\sf (3)/(8)`

Explanation:

Probability is a measure of how likely events are to happen.

When all the possible outcomes are equally likely, we can use this formula to calculate the probability of an event happening:

`\sf P(event)=\frac{\textsf{Number of outcomes where event happens}}{\textsf{Total number of possible outcomes}}`

There are 8 unique letters in the word COMPUTER, so the total number of possible outcome is 8.

If the chosen letter is neither in the word MET nor in the word UP, then it cannot be M, P, U, T or E.

Therefore, it can only be C, O or R.

Therefore, the number of outcomes where the event happens is 3, since there are 3 possible letters that are not in the word MET nor in the word UP.

Plugging these values into the formula gives us the probability of a letter chosen at random not being in the word MET or UP (so being the letter C, O or R):

`\sf P(Choosing\;letter\;C,\;O\;or\;R)=(3)/(8)`