Answer:
(d) y = -5/3x+20
Explanation:
You want the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15,-5).
Slope
The slopes of perpendicular lines are opposite reciprocals of one another. The slope (m') of the perpendicular line is ...
m' = -1/m . . . . . where m is the slope of the given line
Application
The given line's equation is in slope-intercept form. The slope of it is the coefficient of x: 3/5. Then the slope of the perpendicular line is ...
m' = -1/(3/5) = -5/3
Only one answer choice is an equation of a line with a slope of -5/3.
y = -5/3x +20