530,954 views
24 votes
24 votes
The region in the first quadrant bounded by the x-axis, the line x = In(pi), and the curve y = sin(ex) is rotated about the x-axis. What is the volume of the generated solid? (5 points)

0.906
0.795
2.846
2.498​

User MIWMIB
by
2.9k points

1 Answer

8 votes
8 votes

Answer:

D

Explanation:

Please refer to the graph below.

So, we want to find the volume of the solid generated by revolving the green area about the x-axis.

We can use the disk method. The disk method is given by:


\displaystyle V=\pi\int_a^bR(x)^2\, dx

Where R(x) is the radius or height of the representative rectangle.

We are integrating from x = 0 to x = ln(π). The height of a representative rectangle is given by y. Therefore, the volume is:


\displaystyle V=\pi\int_0^(\ln(\pi))(\sin(e^x))^2\, dx

Simplify:


\displaystyle V=\pi\int_0^(\ln(\pi))\sin^2(e^x)\, dx

Approximate. So, the volume of the generated solid is:


V\approx 2.498\text{ units}^3

The solid is shown in the second figure.

(Courtesy of WolframAlpha.)

The region in the first quadrant bounded by the x-axis, the line x = In(pi), and the-example-1
The region in the first quadrant bounded by the x-axis, the line x = In(pi), and the-example-2
User Rohith Murali
by
3.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.