Question

What is the equation of the axis of symmetry for this function? H(x) = -X2 + 10x - 11 x = -5 0 x= -10 x = 5 x = 10

Answer 1

Given:

The equation of a quadratic function is:

`H(x)=-x^2+10x-11`

To find:

The equation of the axis of symmetry for the given function.

Solution:

If a quadratic function is
`f(x)=ax^2+bx+c`, then the equation of the axis of symmetry is:

`x=-(b)/(2a)` ...(i)

We have,

`H(x)=-x^2+10x-11`

Here,
`a=-1,b=10,c=-11`. So, the equation of axis of symmetry by using (i), is

`x=-(10)/(2(-1))`

`x=-(10)/(-2)`

`x=5`

Therefore, the correct option is C.