Question

In 1920, a 6.5 × 104 kg meteorite was found in Africa. Suppose a meteorite with this mass enters Earth’s atmosphere with a speed of 1.0 km/s. What is the change in the meteorite’s momentum if an average constant force of −1.7 × 106 N acts on the meteorite for 30.0 s? How far does the meteorite travel during this time?

Answer 1

Below

Step-by-step explanation:

Find acceleration:

F = ma -1.7 x 10^6 = 6.5 x 10^4 * a so a = - 26.2 m/s^2

vf = vo + at

= 1000 m/s + (-26.2)(30) = 215.4 m/s

change in momentum (6.5 x 10^4) ( 1000 - 215.4) = 51 000 000 kg m /s

d = vo t - 1/2 at^2

= 1000(30) - 1/2 (26.2)(30^2) = 18,210 m