Question

A semicircle is cut out of a rectangular paperboard measuring 24in long and 18in wide, as shown below. What is the perimeter of the paperboard that remains after the semicircle is removed? Do not round any intermediate computations. Round your final answer to the nearest hundredth and be sure to include the correct unit. If necessary, refer to the list of geometry formulas. 18in 24in

Answer 1

Explanation:

we can't see the picture of the "paperboard" but I'm going to guess it looks like my drawing that i've attached.

the 3 side of the rectangle are pretty straight forward, I'm sure you've got that part figured out right?

so then we need the circle part, we can find the distance all the way around the circle , and then divide that by two to find our cut out perimeter.

circumference = 2
`\pi`r = 2*
`\pi`*12 = 75.39822369

but recall, that's all the way around the circle to divide by 2 to get one half of the circle

75.39822369 / 2 =37.69911184

add the 3 sides, and our 37.69911184, then round to the nearest 100th.

37.70 is the nearest 100th if you were not sure. Now just add the other 3 straight sides , and you got it :)