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Write the equation of the line parallel to x+7y=21 that passes through the point (–14, 4).

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Answer:

Equation of line is given as y = mx + c, where m is the gradient and c is the y-intercept.

First, rearrange x + 7y = 21 into y = mx + c form.

x + 7y = 21

7y = - x + 21

y = -1/7x + 3

Parallel lines have the same gradient so gradient of line is -1/7.

Equation of line is now y = -1/7x + c.

Substitute (-14,4) into the equation to find c.

4 = -1/7(-14) + c

4 = 2 + c

c = 2

Hence, equation of line is y = -1/7x + 2.

User Jonathan Larouche
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