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A wallet contains five $10 bills, four $5 bills, and six $1 bills (nothing larger). If the bills are selected one by one in random order, what is the probability that at least two bills must be selected
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A wallet contains five $10 bills, four $5 bills, and six $1 bills (nothing larger). If the bills are selected one by one in random order, what is the probability that at least two bills must be selected to obtain a first $10 bill?.

User Dughall
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1 Answer

7 votes
Answer:
1/3 chance (I'm pretty sure)
Step-by-step explanation:

So this is what I did I added all the values: 5+4+6=15 and there are 5 $10 bills, so it would be 5/15, or simplified, 1,3, I hope this answer helps, I tried my best
User Qfwfq
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