Question

if it takes a ball dropped from rest 2.111 s to fall to the ground, from what height h was it released?

Answer 1

Answer: 21.84 m

Step-by-step explanation:

use the formula h=V-initial + 1/2 a
`t^(2)`

Since the ball starts at rest, v-initial = 0, so the first term drops out

h = 1/2a
`t^(2)` a = g = 9/8 m/s2

h = 1/2 (9.8 m/s2)
`(2.111^(2))` = 21.84 m