Question

1.

The equation of the line having x-intercept -3/2, y-intercept 3/4 is
1) 3x + 2y - 6 = 0
2) 2x - 4y + 3 = 0
3) 2x + 3y - 5 = 0
4) 4x - 3y - 12 = 0
O
1)
2)
O
3)
O
4)​

Answer 1

2nd option

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (-
`(3)/(2)`, 0) and (x₂, y₂ ) = (0,
`(3)/(4)` )

m =
`((3)/(4)-0 )/(0+(3)/(2) )` =
`((3)/(4) )/((3)/(2) )` =
`(1)/(2)` and c =
`(3)/(4)` , then

y =
`(1)/(2)` x +
`(3)/(4)` ( multiply through by 4 to clear the fractions )

4y = 2x + 3 ( subtract 4y from both sides )

0 = 2x - 4y + 3 , that is

2x - 4y + 3 = 0 ← equation of line