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Shelby completes one lap of a go-cart track every 40 seconds. Laura completes one lap of the same track every 30 seconds. Suppose Shelby and Laura cross the starting line at the same time. a. How many
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Shelby completes one lap of a go-cart track every 40 seconds. Laura completes one lap of the

same track every 30 seconds. Suppose Shelby and Laura cross the starting line at the same time.
a. How many seconds will pass before they cross the starting line at the same time again?
b. How many laps will Shelby have completed in that time?
c. How many laps will Laura have completed in that time?

User David Weng
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1 Answer

3 votes

Answer:

Below in bold.Step-by-step explanation:a. This is the Lowest common multiple of 30 and 40 which is120 seconds.b. In 120 seconds Abram had completed 120/40= 3 laps.c. Joshua completed 120/30 = 4 laps.

Explanation:

User Veshraj Joshi
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