Answer: ACCELARATION = 0.462M/S²
Explanation: INITIAL VELOCITY (VI) = 8M/S
DISTANCE COVERED (S) = 744M
TIME (t) = 42 S
ACCELERATION (A)= ?
BY APPLYING 2ND EQUATION OF MOTION
S = VIT +1/2 AT²
744 = 8 X 42 +1/2 A X42²
744 - 336 = 1/2 A X 42²
408 X 2/1764 = A
A = 816 /1764
A = 0.462M/S²