Answer:1. How many moles is 400.0 g of Al 2(SO4)3?
Mol = mass/molar mass
Mol = 400.0g/342g/mol = 1.169 mol
2. Which is the percent composition of bromine in the compound NaBr?
% Br = (mass Br/mass NaBr) x 100
% Br = (79.90g/102.88g) x 100 = 77.7%
3.How many molecules are in 3.6 grams of NaCl?
Molecules NaCl = 3.6g NaCl x 6.02 x 1023 NaCl molecules = 3.7 x 1022 molecules
58.43g NaCl
4.How many grams are in 1.946 moles of NaCl?
From Mol = mass/molar mass,
Mass = mol x molar mass
Mass NaCl = 1.946 mol x 58.43 g = 113.7 g
Step-by-step explanation: