Answer:q = - 9 and r = - 10
Explanation:
since g(x) is divided by (x - 1) with remainder - 12, then (1) = 4(1)³ + q(1)² + r + 3 = - 12, that is 4 + q + r + 3 = - 12
q + r + 7 = - 12 ( subtract 7 from both sides )
q + r = - 19 → (1)
Since (x - 3) is a factor of g(x), then
g(3) = 4(3)³ + q(3)² + 3r + 3 = 0, that is
108 + 9q + 3r + 3 = 0
9q + 3r + 111 = 0 ( subtract 111 from both sides )
9q + 3r = - 111 → (2)
The 2 equations to be solved simultaneously are (1) and (2)
Multiply (1) by - 3
- 3q - 3r = 57 → (3)
Add (2) and (3) term by term to eliminate r
6q = - 54 ( divide both sides by 6 )
q = - 9
Substitute q = - 9 into (1)
- 9 + r = - 19 ( add 9 to both sides )
r = - 10
Hope the helps!!! ❤️