Question

What is the partial pressure (in atm) of co₂ at 468. 2 k in a 25. 0 l fuel combustion vessel if it contains 60. 0 grams co₂, 82. 1 g h₂o, and 7. 30 mol vaporized, yet uncombusted fuel?.

Answer 1

2.09 atm

Step-by-step explanation:

Given: Temperature of system. volume of system, and masses of component gasses.

In order to get the mole fraction which we will use later, convert the 60.0 g CO2 and 82.1 g H20 into moles and add the number of moles you got yo 7.30.

(60.0g CO2 / 44.01 g/mole) + (82.1g H20/18.02) + 7.30 moles unknown fuel

This should work out to about 13.22 moles total. Then, plug in your numbers to the ideal gas law (PV=nRT or P=nRT/V). This will result in the total pressure of the system. p=(13.22 moles)x(0.08206 l*ATM/moles *K)x(468.2)/25.0L. This equation results in a total of 20.3 atm. According to Daltons law of partial pressure, the mole fraction (moles of a gas over total moles) of a given gas times the total pressure of the container gives the partial pressure.

(1.36/13.22) * 20.3 atm=2.09 atm