Question

What is the equation of the line that passes through the point (-1,5) and has a slope of -3

Answer 1

`(\stackrel{x_1}{-1}~,~\stackrel{y_1}{5})\hspace{10em} \stackrel{slope}{m} ~=~ - 3 \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{- 3}(x-\stackrel{x_1}{(-1)}) \implies y -5= -3 (x +1) \\\\\\ y-5=-3x-3\implies {\Large \begin{array}{llll} y=-3x+2 \end{array}}`