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A construction worker earns an average bi-weekly net pay of $1,764.00. Which compound inequality correctly shows the amount of money, t, the worker can spend if the monthly budget for food is between 10% and 20%?

$176.40 ≤ t ≤ $352.80
$352.80 ≤ t ≤ $706.50
$382.20 ≤ t ≤ $764.40
$420.42 ≤ t ≤ $573.30

User Tanman
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2 Answers

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Final answer:

The worker's bi-weekly net pay is $1,764.00. The correct compound inequality for the monthly budget for food is $352.80 ≤ t ≤ $705.60

Step-by-step explanation:

The worker's bi-weekly net pay is $1,764.00.

To find the monthly budget for food, we need to multiply the bi-weekly net pay by 26 (the number of bi-weekly periods in a year) and then multiply it by the percentage range (10% to 20%) to get the range of money the worker can spend on food.

The correct compound inequality is $352.80 ≤ t ≤ $705.60

User Pach
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Answer:

$382.20 ≤ t ≤ $764.40

Step-by-step explanation:

Hello, so first we would need to convert bi-weekly pay to monthly income.

First we would times $1,764.00 by 26

1764.00 × 26 = 45864

Then we would divide 45864 by 12

45864 ÷ 12 = 3822.

Then we calculate how much the worker can spend if their monthly budget for food is in between 10% and 20%

3822 × 10% = 382.20

3822 × 20% = 764.40

So, we can see the correct answer is $382.20 ≤ t ≤ $764.40.

User Joshua Finch
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4.9k points